SQL ERROR

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'One' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryengl' at line 1

SELECT candidates.dictionary AS id, COUNT(DISTINCT candidates.deid) AS total, IF(dictionary.level>0,1,0) AS haslevel, dictionarysynonyms.dictionary AS ds FROM (SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='You' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='Person' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='\' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='One' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='Someone' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='man' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='One Who' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='Native Of' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='Resident Of' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='Female Counterpart' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='Your' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=2314 AND dictionaryenglish.english='i,i myself,alter,alter ego,alterum,better self,ego,ethical self,he,her,herself,him,himself,inner man,inner self,it,me,my humble self,myself,number one,oneself,other self,ourselves,self,she,subconscious self,subliminal self,superego,them,themselves,they,yours truly,yourself,yourselves') candidates INNER JOIN dictionary ON dictionary.id=candidates.dictionary LEFT JOIN dictionarysynonyms ON dictionarysynonyms.dictionary=2314 AND dictionarysynonyms.synonym=candidates.dictionary WHERE (dictionarysynonyms.ismatch IS NULL OR dictionarysynonyms.ismatch=1) GROUP BY candidates.dictionary ORDER BY ismatch DESC, total DESC, haslevel DESC, dictionary.level LIMIT 40