SQL ERROR

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Width' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryen' at line 1

SELECT candidates.dictionary AS id, COUNT(DISTINCT candidates.deid) AS total, IF(dictionary.level>0,1,0) AS haslevel, dictionarysynonyms.dictionary AS ds FROM (SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=30555 AND dictionaryenglish.english='Wooden teeth' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=30555 AND dictionaryenglish.english='Beater' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=30555 AND dictionaryenglish.english='Weaver\' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=30555 AND dictionaryenglish.english='Width' UNION ALL SELECT dictionaryenglish.dictionary AS dictionary, dictionaryenglish.id AS deid FROM dictionaryenglish WHERE dictionaryenglish.`member`=1 AND dictionaryenglish.dictionary!=30555 AND dictionaryenglish.english='Reed [plate 1]') candidates INNER JOIN dictionary ON dictionary.id=candidates.dictionary LEFT JOIN dictionarysynonyms ON dictionarysynonyms.dictionary=30555 AND dictionarysynonyms.synonym=candidates.dictionary WHERE (dictionarysynonyms.ismatch IS NULL OR dictionarysynonyms.ismatch=1) GROUP BY candidates.dictionary ORDER BY ismatch DESC, total DESC, haslevel DESC, dictionary.level LIMIT 40